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xenn [34]
3 years ago
6

What is the domain of y=tan x?​

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

The domain of the function y=tan(x) ) is all real numbers except the values where cos(x) is equal to 0 , that is, the values π/2+πn for all integers n . The range of the tangent function is all real numbers.

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HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 10PTS PLUS BRAINLEIST!!!!!!!!!!!!!! THIS!!!!! IS!!!!! URGENT!!!!!!
Shtirlitz [24]
1.
4 \pm \sqrt{49} = 4 \pm 7 = 4 + 7 or 4 - 7 = 11 or -3

2.
pi is a real number. It is not imaginary or complex, so it definitely belongs to the set of real numbers.
pi is not a whole number or a rational number. It cannot be written as a fraction of integers. pi is irrational.
Therefore, pi is real and irrational.
3 0
3 years ago
Mr. Bloop can high jump 5.75 feet. How far short is that of Charles Austin's record of 7 ft 10 in?
a_sh-v [17]

Answer:

5.75 feet is the same as 5 ft 9 inches (because 12 in = 1 ft and 0.75 * 12 = 9 so its 9 in). 7 ft 10 in - 5 ft 9 in = 2 ft 1 in.

6 0
4 years ago
100 points , please help. I am not sure if I did this correct if anyone can double-check me thanks!
Nookie1986 [14]

Step-by-step explanation:

\lim_{n \to \infty} \sum\limits_{k=1}^{n}f(x_{k}) \Delta x = \int\limits^a_b {f(x)} \, dx \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times k

In this case we have:

Δx = 3/n

b − a = 3

a = 1

b = 4

So the integral is:

∫₁⁴ √x dx

To evaluate the integral, we write the radical as an exponent.

∫₁⁴ x^½ dx

= ⅔ x^³/₂ + C |₁⁴

= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)

= ⅔ (8) + C − ⅔ − C

= 14/3

If ∫₁⁴ f(x) dx = e⁴ − e, then:

∫₁⁴ (2f(x) − 1) dx

= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx

= 2 (e⁴ − e) − (x + C) |₁⁴

= 2e⁴ − 2e − 3

∫ sec²(x/k) dx

k ∫ 1/k sec²(x/k) dx

k tan(x/k) + C

Evaluating between x=0 and x=π/2:

k tan(π/(2k)) + C − (k tan(0) + C)

k tan(π/(2k))

Setting this equal to k:

k tan(π/(2k)) = k

tan(π/(2k)) = 1

π/(2k) = π/4

1/(2k) = 1/4

2k = 4

k = 2

8 0
4 years ago
in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
Point F is a centroid of the triangle BDE. If AB = 24 cm, what is BE?
Alex17521 [72]

Answer: i know this is way late, but it’s 48

Step-by-step explanation:

Since point A is the separation of BE, both sides of the separation are equivalent, the are congruent. Since AB=24, you add 24+24 to get 48.

(I also just answered this question on homework and got it right, this is just how I did it.)

4 0
3 years ago
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