Answer: Graph D will be correct graph for the given function.
Explanation:
Given function 
Since it is a bi-quadratic equation thus it must have 4 roots and (0,1) is one of its point.
Moreover, the degree of the function is even thus the end behavior of the function is
, as 
and as 
In graph A, function has four root but it does not have the end behavior same as function f(x).( because in this graph 
, as and , as .) so, it can not be the graph of given function.
In graph B, neither it has four root nor it has the end behavior same as function f(x).(because in this graph as and as .) so, it can not be the graph of given function.
In graph C, neither it has four root nor it has the same end behavior as function f(x).(because in this graph as and as
.) so, it also can not be the graph of given function.
In graph D it has four root as well as it has the same end behavior as the given function. Also it passes through the point (0,1).
Thus, graph D is the graph of given function.
Answer:
an exponential equation has the form y=ar^x where y=final amount, a=initial amount, r=rate, and x=time, in this case
y=200(1.18)^x
Step-by-step explanation:
As <em>x</em> → 10 from above, <em>h(x)</em> is steadily approaching 18.5.
You can either find the roots of the quadratic formula using the quadratic formula two find the halfway point or you can use the formula t=-b/2a. Both of the two methods gives you the axis of symmetry (the t value for the vertex).
I will use the second method since I don't like using the quadratic formula.
t=-32/(2x-16)
t=1 second
After you find the t value for the axis of symmetry, you plug it into the formula of the graph to find the height.
h=-16+32+14
h=30 feet
Answer:
180
Step-by-step explanation:
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