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Dahasolnce [82]

3 years ago

12

Ed is parallel to ab..can someone help me with the proof towards this?

1 answer:

NemiM [27]3 years ago

7 0

Answer:

Area_ACD = [AC*CD*sinC]/2

Area_BCE = [BC*CE*sinC]/2

AC*CD = BC*CE (as Thales theorem AC/CE = BC/CD)

Then, Area_ACD = Area_BCE

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