Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Answer:
deal with the rectangle first A = l X w
4 X 12 = 48 squared cm
semi circle
Area of a circle πr^2
12/2 = 6, radius = 6
π6^2 = 113.097335
113.097335/2 = 56.5486677
56.5 + 48 = 104.5 squared cm
Well,
26.50
In this case, the hundredths place is the 0.
Since there are no more digits after that, 26.50 must already be rounded to the nearest hundredth.
26.50 is the final answer.
The formula for finding the area of a square is:
The formula for finding the area of a triangle is:
So for the square the area would be:
The area for the triangle would be:
You have to multiply your 20cm by 6cm and your final answer being 120 because 0 times 6 is zero and 2 times 6 is 12, then that getting you 120
