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3 years ago

What is the mulitplicative rate of change for the exponential function f(x) = 2 (5over2) to the negative x power ?

Mathematics

1 answer:

mylen [45]3 years ago

5 0

Answer:

2/5

Step-by-step explanation:

f(x) = 2(5/2)^-x = 2(2/5)^x

The multiplicative rate of change is the base of the positive exponent, 2/5.

You might be interested in

How do you find the answer ?

jeka94

I think first you must Unification of denominatorsit will 60 for (3,4,5) so you will get
2\5 = 24\60
1\4 = 15\60
1\3 = 20 \60
then you divide each one apart then multiply by total number (3,800)
so :
24\60 * 3800 = 1520
15\60 * 3800 = 950
20 \60 * 3800 = 1267
_____
note : when you will gather results you will get Approximate number to 3800

i hope i helped

5 0

4 years ago

The question is too hard

TiliK225 [7]

Answer:

Step-by-step explanation:

7(g-9)+12=26

7(g-9)+12-12=26-12

7(g-9)=14

7(g-9)/7=14/7

g-9=2

g-9+9=2+9

g=11

5 0

2 years ago

Read 2 more answers

Help please guys thanks

ss7ja [257]

Answer:

Step-by-step explanation:

sqrt_{4}(81)^5=(81^(5))^(1/4)=81^(5/4)

6 0

3 years ago

Read 2 more answers

Please help me right away. There are 2 problems.

koban [17]

For #6;

We know that there are 46% male students and 30% of them are seniors. This means that we have to assume that 30% of the male students are seniors and that 30% of the female students are seniors. Taking 30% of 46% gives us 13.8%.

For #7;

We are looking for the possibility that we choose a junior student (22%) or a sophomore student (28%). This adds up to 50% (22%+28% = 50%). That is out answer.

7 0

3 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick <em>different colors in the first four pick</em>.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

4 years ago