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steposvetlana [31]
3 years ago
11

Can someone help me please?!

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

Both are the same

Step-by-step explanation:

I found the mean and median and both are the same witch is 8.5

allochka39001 [22]3 years ago
3 0

Answer:

Median

Step-by-step explanation:

The median is greater than the mean because the average number of instruments on desks were 9.07, but the two middle numbers were 9 and 10 which gives us a median of 9.5.

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If Angelica is 5 steps to the right of the classroom door and Brion is 12 steps to the left
Nimfa-mama [501]

Angelica is 5 steps to the right while Brion is 12 steps to the left it is 17 steps because theyre going in the opposite directions :P

<em>please give brainly if you can</em>

7 0
3 years ago
Y=x+2<br> 3x+3y=6<br> solving systems by substitution
motikmotik

Answer:6

Step-by-step explanation:Reorder

2

2

and

−

x

-

x

.

y

=

−

x

+

2

y

=

-

x

+

2

3

x

+

3

y

=

6

3

x

+

3

y

=

6

Replace all occurrences of

y

y

in

3

x

+

3

y

=

6

3

x

+

3

y

=

6

with

−

x

+

2

-

x

+

2

.

y

=

−

x

+

2

y

=

-

x

+

2

3

x

+

3

(

−

x

+

2

)

=

6

3

x

+

3

(

-

x

+

2

)

=

6

Simplify

3

x

+

3

(

−

x

+

2

)

3

x

+

3

(

-

x

+

2

)

.

Tap for more steps...

y

=

−

x

+

2

y

=

-

x

+

2

6

=

6

6

=

6

Since

6

=

6

6

=

6

, the equation will always be true.

y

=

−

x

+

2

y

=

-

x

+

2

Always true

Remove any equations from the system that are always true.

y

=

−

x

+

2

6 0
3 years ago
Please help!!!
JulijaS [17]

Answer:

the function is increasing from x-2

7 0
3 years ago
What is HL???<br><br> HL=__<br><br> Image Below
Advocard [28]

Consider a trapezoid GJKF with:

GH=JH (hypothesis)

FL=KL (hypothesis)

so HL is the median of trapezoid GJKF

so: HL=1/2(2.5+1.2)=1.85

4 0
2 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
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