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steposvetlana [31]
3 years ago
11

Can someone help me please?!

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

Both are the same

Step-by-step explanation:

I found the mean and median and both are the same witch is 8.5

allochka39001 [22]3 years ago
3 0

Answer:

Median

Step-by-step explanation:

The median is greater than the mean because the average number of instruments on desks were 9.07, but the two middle numbers were 9 and 10 which gives us a median of 9.5.

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Y=x+2 2x-y=-4 Solve the systems of equations
larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0
3 years ago
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What is the value of m? 12+(7+m)=30<br><br> 11<br> 19<br> 25<br> 35<br> 49
Marat540 [252]
The answer is 11
hope that helps
4 0
3 years ago
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PLEASE ANWSER ASAPPPPLL I NEED IT QUICK PLS SHAWTY
Marianna [84]

Answer:

c

Step-by-step explanation:

3 and 3/7 ok hope it helps

5 0
3 years ago
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The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
5th grade math. correct answer will be marked brainliest.
nordsb [41]

Answer: 60

30

Step-by-step explanation: that’s the first two, good luck!

4 0
3 years ago
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