Answer:
Step-by-step explanation:
The answer is 1.3
Answer: C. x = 6; m∠XOY = 18
Step-by-step:
We see that ZOW and WOX are supplementary, meaning the sum of their angles equal 180.
We also know that WOY is a right angle and equals 90.
Now we can solve
180-108 = 72
90 - 72 = 18
XOY = 18
Because 3x = 18, we know that x = 18 by dividing 18 by 3
The angles are the only constraint here that counts. If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees. Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle. If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.
The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.
Answer:
Option 2: 
Step-by-step explanation:
Given:
From the triangle shown below;
A triangle QRS with angle QRS = 90°, ∠QSR = 30°.
Side QR = 5, SQ = 10 and RS = 5√3
Now, we know from trigonometric ratio that,
Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,
Therefore, the value of sine of 30° is one-half. So, second option is correct.
Answer:
x = -34.8
Step-by-step explanation:
<h2><u>solve the equation</u></h2>
2(x-3)
= 2x - 6
7(x + 24 )
= 7x + 168
put the equation together
2x - 6 = 7x + 168
now make x subject of formula:
2x - 7x = 168 +6
-5x = 174
x = 174/ -5
<h3><u>x = -34.8 </u></h3>
