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3 years ago

Rite an equation of each line that passes through the following points in slope-intercept form:

Mathematics

1 answer:

finlep [7]3 years ago

5 0

Answer:

y = (8/5)x - 3

Step-by-step explanation:

Slope:

(-19-5)/(-10-5)

= -24/-15 = 8/5

y = (8/5)x + c

5 = (8/5)(5) + c

c = 5 - 8 = -3

y = (8/5)x - 3

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(N * 3) + 6 - (n * 2) = n + 3 what is value of n

GalinKa [24]

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Papessa [141]

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harkovskaia [24]

Answer:

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3 years ago

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Alik [6]

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4 years ago

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Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%

Nataly [62]

Step-by-step explanation:

<h3> $\sec \alpha \sqrt{1 - \sin ^{2} \alpha } = 1$ </h3>

Prove the LHS

Using trigonometric identities

That's

<h3> $\cos ^{2} \alpha = 1 - \sin^{2} \alpha$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $\sec \alpha \sqrt{ \cos^{2} \alpha }$ </h3>

<h3> $\sqrt{ { \cos }^{2} \alpha } = \cos \alpha$ </h3>

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<h3> $\sec \alpha \times \cos \alpha$ </h3>

Using trigonometric identities

<h3> $\sec \alpha = \frac{1}{ \cos \alpha }$ </h3>

<u>Rewrite the expression</u>

That's

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Reduce the expression with cos a

We have the final answer as

As proven

Hope this helps you

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