Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28
Answer:
x=5
Step-by-step explanation:
23-3= 4x or 20
that means 4x is equal to 20
20 divided by 4 is 5
so x is equal to 5
Answer:
19958400 ways
Step-by-step explanation:
As the question involves arrangement, permutation will be used.
P(n,r) = n! / (n-r)!
Here
n=12
and
r = 8
So,
P(12,8) = 12!/(12-8)!
= 12!/ 4!
=19958400 ways
Therefore, the 8 objects from 12 can be arranged in 19958400 ways ..
The slope can be found using rise over run
the line goes up 5 and over 10
so the slope would be 5/10 or 1/2
therefore the equation of the line is:
y=1/2x
Answer:
5
Step-by-step explanation:
-7 x 4 = -28
-7 x -6 = 42
-28 + 42 = 14
14 - 9 = 5
