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3 years ago

Sinplify 12-3[2x-5(x-1)]

Mathematics

1 answer:

Inessa05 [86]3 years ago

5 0

12-3[2x-5(x-1)]

12-3[2x-5x+5]

12-3[-3x+5]

12+9x-15

9x-3

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Answer:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

Step-by-step explanation:

Given

$S = \{V,W,X,Y,Z\}$

$n(S) = 5$

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

$P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20$

$P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20$

$P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20$

$P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20$

$P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20$

So, the probability model is:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

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Answer:

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And then the value of t would be:

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And rounded to the nearest tenth would be 9.2 years.

Step-by-step explanation:

For this case since we know that the interest is compounded continuously, then we can use the following formula:

$A =P e^{rt}$

Where A is the future value, P the present value , r the rate of interest in fraction and t the number of years.

For this case we know that P = 100000 and r =0.12 we want to triplicate this amount and that means $A= 300000$ and we want to find the value for t.

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$3 = e^{0.12 t}$

Now we can apply natural logs on both sides;

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