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3 years ago

Need help please please

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

6 0

Step-by-step explanation:

Three and one half

$= 3 \frac{1}{2}$

Less than symbol ( < )

Five and one half

$= 5\frac{1}{2}$

So, equation will be,

$3 \frac{1}{2} < 5 \frac{1}{2}$

Hence, your chosen option is correct 

Lera25 [3.4K]3 years ago

3 0

Answer:

3 1/2<5 1/2

Step-by-step explanation:

The first answer is correct

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A supervisor finds the mean number of miles that the employees in a department live from work. Which mileage is within a z-score

Vikentia [17]

The z-score tells you how many standard deviations from the mean.

1.5 * 3.6 = 5.4 miles 

So anything within 5.4 miles of the average (29). 

The range would be: 
29 - 5.4 = 23.6 
to: 
29 + 5.4 = 34.4 

23.6 ≤ x ≤ 34.4 

Answer: 
B) 24 miles

7 0

3 years ago

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Where does the normal line to the parabola y = x − x2 at the point (1, 0) intersect the parabola a second time?

Ksivusya [100]

Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)

we just need the slope

take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1

the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation

solve for where y=x-1 and y=x-x² intersect

set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero

x-1=0
x=1
we got this point already

x+1=0
x=-1
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y=-1-(-1)²
y=-1-(1)
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7 0

3 years ago

Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra

lys-0071 [83]

Answer:

Step-by-step explanation:

Directions

Draw a circle
Dear a chord with a length of 24 inside the circle. You just have to label it as 24
Draw a radius that is perpendicular and a bisector through the chord
Draw a radius that is from the center of the circle to one end of the chord.
Label where the perpendicular radius to the chord intersect. Call it E.
You should get something that looks like the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.

Givens

AC = 13 inches Given

CB = 24 inches Given

CE = 12 inches Construction and property of a midpoint.

So what we have now is a right triangle (ACE) with the right angle at E.

What we seek is AE

Formula

AC^2 = CE^2 + AE^2

13^2 = 12^2 + AE^2

169 = 144 + AE^2 Subtract 144 from both sides.

169 - 144 = 144-144 + AE^2 Combine

25 = AE^2 Take the square root of both sides

√25 = √AE^2

5 = AE

Answer

The 24 inch chord is 5 inches from the center of the circle.

4 0

1 year ago

Read 2 more answers

Need help with A and C please :)

Dennis_Churaev [7]

First step: name the sides according to geometry standards, namely, the sides are named the same lowercase letter as the opposing angle. A revised diagram is shown.

Second step: we need to know the relationships of the trigonometric functions.

cosine(A)=cos(63) = adjacent / hypotenuse = AC/AB .................(1)

sine(A)=sin(63) = opposite / hypotenuse = CB/AB .......................(2)

We're given AB=7, so

using (1)

AC/AB=cos(63)

AC=ABcos(63)=7 cos(63) = 7*0.45399 = 3.17993 = 3.180 (to three dec. figures)

Using (2)

BC/AB=sin(63)

BC=ABsin(63) = 7 sin(63) = 7*0.89101 = 6.237 (to three dec. figures).

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lyudmila [28]

Answer:

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Step-by-step explanation:

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