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2 years ago

C = 3p + 5 Solve for c.

1 answer:

7 0

Step 1: Move variable to the left side and change its sign
-3p+c=5

Step 2: Move variable to the right side and change its sign
-3p=5-c

Step 3: “Divide both sides of the equation by
-3”
P=-5/3 + 1/3c

Step 4: “The final solution is
P= -5/3 + 1/3c

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

2 years ago

Need as much help as I can get before 7 minutes are over

andriy [413]

Answer:

think the answer is E but not 100%. been a while. let me know either way

7 0

3 years ago

I really need help quick I’ve been working this out for 1 hour already

wolverine [178]

Answer:

Step-by-step explanation:

Hope this helps

4 0

2 years ago

A map has a scale of 3 cm and 20 cm which statement is true or false two cities are actually 66 cm part are9.9 cm part

victus00 [196]

Answer:
Answer options
A. Two cities that are 7.5 cm apart on the map are actually 50 km apart.
D. Two cities that are actually 66 km apart are 9.9 cm apart on the map.
Step-by-step explanation:
Step 1
Indicate the scale as shown;
3 cm : 20 km, meaning 3 cm on the map represents 20 km on the ground
A). what does 7.5 cm represent on the ground
Distance on ground=(7.5×20)/3=50 km
B). what does 4 cm represent on the ground
Distance on ground=(4×20)/3=26.67 km
C). what does 45 km on ground represent on the map
Distance on map=(45×3)/20=6.75 cm
D). what does 66 km on ground represent on the map
Distance on the map=(66×3)/20=9.9 cm

8 0

2 years ago

If x=-1, x^5+x+4+x^3+x

DedPeter [7]

Answer:

Step-by-step explanation:

yeah-ya.............. right?

8 0

2 years ago

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