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weeeeeb [17]
2 years ago
14

C = 3p + 5 Solve for c.

Mathematics
1 answer:
e-lub [12.9K]2 years ago
7 0
Step 1: Move variable to the left side and change its sign
-3p+c=5

Step 2: Move variable to the right side and change its sign
-3p=5-c

Step 3: “Divide both sides of the equation by
-3”
P=-5/3 + 1/3c

Step 4: “The final solution is
P= -5/3 + 1/3c
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1.What are the values of the 6s in 36,621?
enot [183]
1) The value of 6s in 36,621 are 6,000 and 600.

first 6 is in the thousands place value while the second 6 is in the hundreds place value.
6 x 1000 = 6,000 and 6 x 100 = 600

2) The first 4 is ten times greater than the second 4 is shown in 354,426

the first 4 is in the thousands place value while the second 4 is in the hundreds place value
4 x 1000 = 4000 and 4 x 100 = 400

based on the question the first 4, which is 4000, is ten times greater than the second 4, which is 400.
we can check if this statement is true either by dividing 4000 by ten or multiplying 400 by ten.

4000/10 = 400 ; 400 x 10 = 4000. therefor, out of the 4 numbers given, the correct one is 354,426

3) The relationship of the two 5s in 552 is shown in 500 ÷ 50 = 10

based on its place value, the first five is in the hundreds place and the second five is in the tens place.

500 ÷ 50 = 10. This equation states that 500 is ten times greater than 50.

4) In 2,077 the first 7 is greater than the second 7 by 10 times.

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70 ÷ 7 = 10 times.


8 0
3 years ago
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:

<span>The interquartile range is the difference between the third and the first quartiles.

The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5

The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
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3 years ago
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Answer:

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Step-by-step explanation:

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