Answer:
1. see attached diagram
2. The dimensions are 75 sqrt(2) by 75 sqrt(2) ft
3. The perimeter is 300 sqrt(2) ft
4. cannot fit 40 machines along the walls
Step-by-step explanation:
We are using a top down view. We have a square building with side length s. The diagonal is 150 ft
Using the Pythagorean theorem
s^2 + s^2 = 150^2
2s^2 = 22500
s^2 =11250
Taking the square root of each side
sqrt(s^2) = sqrt(11250)
s = sqrt(6225*2)
s = 75 sqrt(2)
The dimensions are 75 sqrt(2) by 75 sqrt(2) ft
The perimeter of a square is given by
P = 4s = 4(75 sqrt(2)) =300 sqrt(2) ft
The perimeter is 300 sqrt(2) ft
Assuming the machines are square ( that they are as wide as they are long) 75 sqrt(2) is approximately 106 ft so you can fit 10 along the wall
Putting them along the top and bottom walls = 20 machines
We are only left with 86 ft along the side walls
86/10 = 8 machines
machines * 2 walls = 16
We can fit 20+16 machines = 36 machines not 40
Answer:
46
Step-by-step explanation:
The order of operations is to multiply before you divide.
2x9= 18
2x14=28
18+28=46
Answer:
s= 14
Step-by-step explanation:
The missing side is s
sin 30° = 7/s switch s and sin 30°
s = 7/sin 30°
sin 30° is 0.5
so :
Answer:
First blank: 15
Second blank: 35%
Step-by-step explanation:
When she starts, n is 0, so the first blank is 15.
If b is 1.35, you are multiplying by that every year, which is the same as adding 0.35 of it, or 35%.
Answer:
b. Multiplying decimals less than one is finding a part of a part.
Step-by-step explanation:
A part of a given number implies a selected part of a given number which can be expressed as a fraction of the number. Example, the half of any number is .
The product of a part and another part can be expressed as;
x =
or,
x =
or,
x = =
The three examples shows: a part x a part.
Therefore, it would be observed that multiplying decimals less than one is the same as finding a part of a part.