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Andreas93 [3]
3 years ago
11

What is the answer??

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0
You have to do the distribute property and then combine the like terms
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What is the value of each expression?
Maru [420]

Answer:

1. -3   2. 3

Step-by-step explanation:

Evaluate each expression is very simple concept in math. When you substitute a particular value for each variable and then act the operations called evaluating expression.

8 0
3 years ago
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How many times dose 25 go into 150
alexandr1967 [171]
The answer is 6.
4 quarters is 1 dollar right?
and if you add 2 more, it will be $1.50
This is the easiest way to memorize how to multiply using the number 25.
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write a simplified polynomial expression in the standard form to represent the area of the rectangle below x-4 5x+2
Ann [662]

The area of the rectangle is 5x^{2} -18x-8

Explanation:

One side of the rectangle is x-4

The another side of the rectangle is 5x+2

The formula to find the area of the rectangle is length × width

Area = length × width

Substituting the values, we have,

\begin{aligned}\text { Area } &=(x-4)(5 x+2) \\&=5 x^{2}+2 x-20 x-8 \\&=5 x^{2}-18 x-8\end{aligned}

Thus, the area of the rectangle is 5x^{2} -18x-8

3 0
3 years ago
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Write down the value of 5^-1
Katarina [22]
Wouldnt it be 0.2 i think
4 0
3 years ago
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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
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