<u>Not sure what you are asking for, but,</u>
<u>Here is an example of a JRU (Join Result Unknown) word problem</u>:
There were _____ kids on the playground. ____ more kids came onto the playground. How many kids are on the playground?
<u>Here is an example of a JCU (Join Change Unknown) word problem:</u>
There were ____ kids on the playground. Some more kids came on the playground. Now there are ____ kids on the playground. How many kids came on the playground?
<u>
Here is an example of a JSU (Join Start Unknown) word problem:</u>
Some kids were on the playground. ____ kids came on the playground. Now there are ____ kids on the playground. How many kids were on the playground at the beginning?
Answer:
Step-by-step explanation:
The given expression is:
Moving the expression to the other side in the fraction changes its sign to opposite. A numerator with negative exponent, when written in denominator will have the positive exponent. Using this rule, we can write:
The exponent 5 can be distributed to both numerator and denominator as shown:
The power of a power can be written as a product. i.e.
So, the expression similar to the given expression and with positive exponents is:
Answer:
d = 14/5
Step-by-step explanation:
The point (-4,2) means that;
At x = -4, y = 2
Now general form of a linear equation is;
Ax + By + C = 0
We are given;
4y = 3x + 6
Rearranging to the form of a linear equation gives;
3x - 4y + 6 = 0
Thus, A = 3, B = -4 and C = 6
Thus, at point (-4,2), distance between them is;
d = (3(-4) - 4(2) + 6)/√(3² + (-4)²)
d = -14/5
We will take the absolute value.
Thus; d = 14/5
