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3 years ago

Which represents a quadratic function?

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

What are the options for the answer?

Step-by-step explanation:

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Which proportion can be used to solve for f in the figure above?

kirill [66]

Answer:

You could use the Pythagnerum Theorem

Step-by-step explanation:

3 0

3 years ago

The coordinates of the vertices for rectangle ABCD are A (2,4), B (6,10), C (9,8) and D (5,2). What

sweet [91]

Answer:

D. $\sqrt{65}$

Step-by-step explanation:

The computation of the length of a diagonal (AC or BD) of the rectangle is shown below:

As we know that

The Diagonal length of AC is

$= (x_2 - x_1)^2 + (y_2 - y_1)^2\\\\= (9 -2)^2 + (8 - 4)^2\\\\= (7)^2 + (4)^2$

$= \sqrt{49 + 16}\\\\= \sqrt{65}$

Therefore correct option is D.

3 0

2 years ago

Base: 11 m, area: 1115.5 m2

Marina86 [1]

101.4

$1115.5 \div 11 = 101.4$

8 0

3 years ago

the flower shop had 40 times as many flowers in one cooler as Julia has in her bouquet the cooler has 120 flowers how many flowe

Softa [21]

Answer:

3 flowers are in Julias bouquet

Step-by-step explanation:

120 divided by 40 = 3

6 0

3 years ago

Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =

vampirchik [111]

Answer:

In this problem, we are given the following functions:

$f(x)=\frac{1}{2}x$

and its inverse function:

$f^{-1}(x)=2x$

First of all, we want to calculate $f(2)$ . This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

$f(2)=\frac{1}{2}\cdot 2 = 1$

Then we want to calculate $f^{-1}(1)$ . We can do it by substituting

x = 1

into $f^{-1}(x)$ . Doing so,

$f^{-1}(1)=2\cdot 1 = 2$

Then we want to calculate $f^{-1}(f(2))$ , which can be found by calculating f(2) and then using it as input for $f^{-1}(x).$ We know that

f(2) = 1

Therefore,

$f^{-1}(f(2))=f^{-1}(1)=2$

Then we want to calculate $f^{-1}(-2)$ , which can be calculated by plugging

x = -2

into $f^{-1}(x)$ . Doing so,

$f^{-1}(-2)=2\cdot (-2)=-4$

Then we want to calculate $f(-4)$ ; by substituting

x = 4

into f(x), we find

$f(-4)=\frac{1}{2}\cdot (-4)=-2$

Finally, we want to find $f(f^{-1}(-2))$

We know already that

$f^{-1}(-2)=-4$

So we have:

$f(f^{-1}(-2))=f(-4)=-2$

7 0

3 years ago

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