<h3>Answer:</h3>
Length: 12 yd
Width: 5.5 yd
<h3>Explanation:</h3>
Let x represent the width of the rectangle in yards. Then 2x+1 can represent the length (double the width plus 1 yard). The area is the product of length and width so we have the relation ...
... x(2x+1) = 66
... 2x² +x -66 = 0
This can be solved using any of several methods. One of them is to factor the equation. To do that, we can look for factors of 2·66 = 132 that differ by 1. Since 132 = 11·12, those are the numbers we're looking for. Then ...
... 2x² +12x -11x -66 = 0 . . . . use our found numbers to rewrite the x term
... 2x(x +6) -11(x +6) = 0 . . . . .factor by grouping
... (2x -11)(x +6) = 0
... x = 11/2 or -6 . . . . . values that make the factors zero. Only the positive value is a useful solution.
... The width of the rectangle is 5.5 yards. Its length is 2·5.5+1 = 12 yards,
Since we are dealing with volume, when one object is 4 times bigger than another, the difference in volume is 4^3 = 64.
6 cm sphere = 4/3 *PI * 6^3
6 cm sphere = 4/3 *PI * 216
6 cm sphere =
<span>
<span>
<span>
904.78 cc
24 cm sphere = </span></span></span>4/3 *PI * 24^3
24 cm sphere = 4/3 *PI * 13,824
24 cm sphere =
<span>
<span>
<span>
57,905.84
</span>
</span>
</span>
cc
Comparing the volumes: <span>57,905.84 / 904.78 = </span><span><span><span>64
</span>
</span>
</span>
<span>
</span>
Answer:
21
Step-by-step explanation:
Answer: 22 hours 11 minutes
<u>Step-by-step explanation:</u>
![22\ hours + \bigg[\dfrac{19}{100}=\dfrac{x}{60}\bigg]\\\\22\ hours + 11\ minutes](https://tex.z-dn.net/?f=22%5C%20hours%20%2B%20%5Cbigg%5B%5Cdfrac%7B19%7D%7B100%7D%3D%5Cdfrac%7Bx%7D%7B60%7D%5Cbigg%5D%5C%5C%5C%5C22%5C%20hours%20%2B%2011%5C%20minutes)
