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lakkis [162]
2 years ago
13

|5c -3|= 1 Solve for C (this is homework help-)

Mathematics
2 answers:
irina [24]2 years ago
4 0

Answer:

Step-by-step explanation:

Dmitriy789 [7]2 years ago
3 0

Answer:

|5c - 3|  = 1 \\ 5c - 3 = 1 \\ 5c = 4 \\ c =  \frac{4}{5} \:  or \:  -  \frac{4}{5}

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What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
german
For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
 For x = 1.25:
 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
 For x = 2:
 f(2) = tan(\frac{2^2}{9})
 f(2) = 0.48
 Then, replacing values we have:
 AVR = \frac{0.48 - 0.18}{2 - 1.25}
 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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