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3 years ago

Simplity. 2+{8-2 [32+5(1+2)]} Enter your answer in the box.

Mathematics

1 answer:

V125BC [204]3 years ago

5 0

Answer:

284

Step-by-step explanation:

You have to start out multiplying the (parentheses), then the [brackets], then the {curly brackets}. After you're done with those you would add 2.

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What is -1/p^-6 ???

wariber [46]

$- \frac{1}{ {p}^{ - 6} } = - \frac{1}{ \frac{1}{ {p}^{6} } } = - {p}^{6}$

4 0

3 years ago

The area of a rectangle is 105 square units. Its width measures 7 units. Find the length of its diagonal. Round to the nearest t

mezya [45]

Answer:

16.6

Step-by-step explanation:

The rectangle has an area of 105. It's width is 7.

1: Find the length

$\frac{area}{width}$ =length

$\frac{105}{7}$ = 15

Length=15

2: Pythagorean theorem

$a^{2} +b^2=c^2$

$7^{2}$ + $15^2=c^2$

49+225= $c^2$

275= $c^2$

$\sqrt{275}$ = $\sqrt{c^2\\}$

16.55≈c

Rounded to nearest tenth

16.6

6 0

3 years ago

Write your answer as a fraction or as a whole mixed number. 2 5/11 - 10 7/11

kaheart [24]

Answer:

-90/11

Step-by-step explanation:

convert each mixed number into a improper fraction

27/11 - 117/11

= -90/11

3 0

3 years ago

Read 2 more answers

nlexa [21]

So say we have the number: 54,321

The 5 would be worth 50,000 meaning it's in the ten thousands place.

The 4 would be worth 4,000 meaning it's in the thousands place.

The difference between them is a zero, so the ten thousands place is 10 times bigger than the thousands place

Hope that helps :)

7 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago