Answer:
The sidewalk moves at 0.5 ft/sec
Josie's speed walking on a non-moving ground is 3.5ft/sec
Step-by-step explanation:
Let x represent the speed of the side walk and y represent her walking speed
It takes Jason's 8-year-old daughter Josie 44 sec to travel 176 ft walking with the sidewalk
Distance = speed × time
176 = (x+y)×44
44x+44y = 176
x+y = 4 .......1
It takes her 7 sec to walk 21 ft against the moving sidewalk in the opposite direction).
21 = (y-x)7
7y - 7x = 21
y - x = 3 ......2
Add equation 1 to 2
2y = 7
y = 3.5 ft/sec
From equation 1
x + y = 4
x = 4 - 3.5 = 0.5
x = 0.5 ft/sec
The sidewalk moves at 0.5 ft/sec
Josie's speed walking on a non-moving ground is 3.5ft/sec
Answer:
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°
Step-by-step explanation:
`From the given picture,
Angle SOP and angle SOR are the linear pairs.
Therefore, sum of these angles will be equal to to 180°.
m∠SOP + m∠SOR = 180° -----(1)
Since, m∠SOP = (7x - 2)° and m∠SOR = (5x + 14)°
[There is a misprint in this question. There should be x in place of y in the measures of the angles]
By substituting these values in the equation (1),
(7x - 2) + (5x + 14) = 180
12x + 12 = 180
12x = 180 - 12
12x = 168
x = 
x = 14
m∠SOP = (7x - 2)° = 96°
m∠SOR = (5x + 14) = 84°
Answer:
Answer to the question:
Step-by-step explanation:
α= 54º
V= 66 ft/s
g= 9.8 m/s²
Vx= V * cos(54º) = 38.8 ft/s
Vy= V * sin(54º) = 53.4 ft/s
<u>PARAMETRIC EQUATIONS:</u>
x(t)= Vx * t
y(t)= Vy * t - (g * t²)/2
Answer:
If it is ax^2 + bx + c = 0 then it is a quadratic equation
Step-by-step explanation:
Answer:
t=16.2 years
Step-by-step explanation:
A=p(1+r/n)^nt
A=$20100
P=$6500
r=7%=0.07
n=4
t=?
t=ln(A/P)/n {ln(1+r/n)}
=ln(20100/6500) / 4{ln(1+0.07/4)}
=ln(3.0923)/4{ln(1+0.0175)}
=ln(3.0923)/4{ln(1.0175)}
=1.1289/4(0.0174)
=1.1289/0.0696
=16.23
To the nearest tenth
t=16.2 years