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3 years ago

What is 257,650 rounded to the nearest ten

2 answers:

azamat3 years ago

7 0

It is round to the nesrest to 60 so the answer is 257,660 because I said it was closer to 60 because 50 it has a 5 and with a 5 you round up

den301095 [7]3 years ago

5 0

The answer is 257,650

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-47=x+15 solve the equation

myrzilka [38]

-47 = x + 15
Rearrange it to isolate x:
-47 - 15 = x
-62 = x

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3 years ago

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If I wash 24 dogs and used 4 bottles of shampoo, How many dogs can I wash with only 1 bottle of shampoo?

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Answer:

Step-by-step explanation:

I hoped it helped!!!

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3 years ago

Find area and circumference of the circle (12.) pls NO links

xxTIMURxx [149]

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Step-by-step explanation:

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3 years ago

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Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

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3 years ago