3 years ago

D. 10 + 11k can someone plzz help meeee plzzzz

Mathematics

1 answer:

torisob [31]3 years ago

8 0

Answer:

(A). $\frac{15}{2}$ + $\frac{33}{4}$ <em>k</em>

Step-by-step explanation:

$\frac{3}{4}$ × 2(2 + 4k + 3 + $\frac{3}{2}$ k ) = $\frac{3}{2}$ ( 5 + $\frac{11}{2}$ k ) = $\frac{15}{2}$ + $\frac{33}{4}$ k

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