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iragen [17]
4 years ago
5

The regression equation y = 4x + 20 approximates the number of people attending a picnic, y, given the number of flyers used to

advertise it, x. Which statement is true?
Mathematics
1 answer:
mash [69]4 years ago
8 0

Complete question :

The regression equation y = 4x + 20 approximates the number of people attending a picnic, y, given the number of flyers used to advertise it, x.

Which statement is true?

a.) For every extra person attending a picnic, the number of flyers used to advertise it increases by 20.

b.) For every extra person attending a picnic, the number of flyers used to advertise it increases by 4.

c.) For every extra flyer used in advertising, the attendance increases by 20 people.

d.) For every extra flyer used in advertising, the attendance increases by 4 people.

Answer: d.) For every extra flyer used in advertising, the attendance increases by 4 people.

Step-by-step explanation:

Given the regression equation; y = 4x + 20;

Where y = number of people attending a picnic

x = number of flyers used to advertise it

In the equation;

y = predicted variable ; x = predictor variable ; gradient or slope = 4

The slope or gradient is the rate of change un the response variable with respect to a unit change in the independent variable.

Here, the slope value is +4 and is thus interpreted to mean that, for each 1 unit change in the independent variable (number of flyers shared), there is a corresponding increase in the response variable (number of attendees) by a unit of 4.

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Which argument is valid?
Vinvika [58]

Answer:

The second one "Ben runs 3 miles a day"

Step-by-step explanation:

6 0
3 years ago
A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t
Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is  1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0)  , then the coordinates of the center of the gymnasium   are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ =  |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0
3 years ago
your family have decided to paint your room. It took 1/2 hour to paint 1/8 of your room. How long will it take to paint your who
Elodia [21]

Answer:

4 hours

Step-by-step explanation:

In  6  hours,  J  paints  1  room

So, in  1  hour,  J  paints  1/6 th of the room

Using similar logic, in  1  hour,  T  paints  1/12 th of the room.

Working together in one hour, they paint  (1/6+1/12) th =1/4  of the room.

1/4  of the room is painted in  1  hour

So,  1  room is painted in  1 1/4=4  hours

5 0
3 years ago
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What's 5 divided by 3 1/3?
VMariaS [17]

Answer:

your answer should be 1.5

Step-by-step explanation:

8 0
2 years ago
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The volume of a right circular cone with radius r and height h is V = pir^2h/3.
Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9  and dr = 6.8 - 5.9 = 0.9

     h = 4  and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b).  The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47  and dr = 6.45 - 6.47 = -0.02

     h = 10  and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0
3 years ago
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