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julia-pushkina [17]
3 years ago
5

Two bikers rode at a constant speed on a 150-meter track. The data here show each biker's distance for a certain part of the rac

e. Who won the race and by how much?
Mathematics
1 answer:
Luda [366]3 years ago
4 0

Answer: 2 then 1

Step-by-step explanation:

Just did it

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From the parking lot at red hill shopping center the angle of the top of the hill is about 25 from the base of the hill the angl
eimsori [14]

Answer:

512 ft.

Step-by-step explanation:

From the parking lot at the Red Hill Shopping Center, the angle of sight (elevation) to the top of the hill is about 25. From the base of the hill you can also sight the top but at an angle of 55. The horizontal distance between sightings is 740 feet. How high is Red Hill? Show your subproblems.

Solution:

Let x be the distance from the base of the hill to the middle of the hill perpendicular to the height, let h be the height of the hill. Therefore:

tan 25 = h/(x + 740)

h = (x + 740)tan 25       (1)

tan 55 = h / x

h = x tan 55        (2)

Hence:

(x + 740)tan 25 = xtan 55

0.4663(x + 740) = 1.428x

0.4663x + 345.07 = 1.428x

0.9617x = 345.07

x = 359 ft.

h = xtan55 = 359 tan(55) = 512 ft.

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3 years ago
Because of the fear of player injury, the San Francisco Seals give their
castortr0y [4]

Answer:22

Step-by-step explanation:

22

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SOMEONE HELP ME WITH THIS!! PLEQSE I BEG PLEASE
Marta_Voda [28]

Step-by-step explanation:

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What is<br> is 1/4 + 9/10y -3/5y +7/8 written in simplest form?
Leviafan [203]

Answer:

Step-by-step explanation:

\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y

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3 years ago
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In order to graduate from Ohio, you need to earn 3 points on an Algebra EOC or score remediation
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