Ask question

Ask question

All categories

3 years ago

5

Marissa spent a total of 240 minutes exercising last week. How many minutes did you spend walking? Show or explain how you got y

our answer

2 answers:

neonofarm [45]3 years ago

8 0

You have to divide 240 and the number of days in a week, then you'll get the answer!

Ksenya-84 [330]3 years ago

6 0

Before answering, did she do all 7 days

You might be interested in

The table shows a proportional relationship.

Alenkasestr [34]

(2,2.8)(4,5.6)
slope = (5.6 - 2.8) / (4 - 2) = 2.8/2 = 1.4

y = mx + b
slope(m) = 1.4
use either point (2,2.8)...x = 2 and y = 2.8
now we sub and find b, the y int
2.8 = 1.4(2) + b
2.8 = 2.8 + b
2.8 - 2.8 = b
0 = b

so ur equation is : y = 1.4x + 0..or just y = 1.4x

8 0

2 years ago

Convert the following to standard form, then write

Ivahew [28]

Answer:

$f(x)=x^2+6x+9$

Step-by-step explanation:

We are required to represent the expression given in the standard form to the quadratic form

Given

$f(x) = (x + 3)^2$

let us square the given expression

f(x)=(x+3)(x+3)

open brackets

$f(x)=x^2+3x+3x+9$

sum the similar terms

$f(x)=x^2+6x+9$

6 0

2 years ago

What is the largest sum your can get when you add 2 3 digit numbers

Ksju [112]

The biggest 3 digits whole number is 999.

Hence, the biggest sum one can do with two of those is 999+999=1998

8 0

3 years ago

Read 2 more answers

Which situation can be represented by the expression <br><br> 5−8

TEA [102]

Answer:

Tammy had 5 dollars left on her credit card but she saw a shirt that cost 8 dollars so now she has -3 dollars in her bank account.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

2 years ago