Answer:
A quick hack is often to partially express some function in terms of a Taylor approximation about x0, since higher order terms of x go to zero if we are considering limits for (x−x0)→0. To really answer your question we need to know what the original question was, that is, about which point do you want the expansion? Let us assume around 0. Then we have the Maclaurin series:
cos(x)=1−12x2+O(x4)
You can add more terms if you need to. Now we write:
ln(1+(−12x2))=…
Do you know the standard Maclaurin series for this function?
Hint: it is of the form ln(1+u)
Step-by-step explanation:
14+ 13y - 13y = 20y - 13y -21 (taking away the smallest y value from both sides)
14 = 7y - 21
14 + 21 = 7y - 21 +21 (+21 on both sides to remove -21 if we do -14 then we will have nothing on other side)
35 = 7y
35/7 = 7y/7 (dividing 7 on both sides)
5 = y
answer is 100% correct no doubts. hope it helped you.
Answer:
x = 1.27
y = 5.18
Step-by-step explanation:
to solve this system of equation by simultaneous equation we say that let
3x+y=9.............................. equation 1
-5x+2y=4 .......................... equation 2
from equation 1
3x+y=9.............................. equation 1
y = 9 -3x.............................. equation 3
substitute the value of y = 9 -3x into equation 2
-5x+2y=4 .......................... equation 2
-5x + 2( 9 -3x) = 4
-5x + 18 - 6x = 4
collect the like terms
18 - 4 = 6x + 5x
14 = 11x
divide both side by 11
14/11 = 11x/11
x = 14/11
x = 1.27
put the value of x = 1.27 into equation 3
y = 9 -3x.............................. equation 3
y = 9 - 3( 1.27)
y = 9 - 3.82
y = 5.18
<em>to check if you are correct put the value of x and y into either equation 1 or equation 2.</em>
<em>3x+y=9.............................. equation 1</em>
<em>3( 1.27) + 5.18 = 9</em>
<em>3.81 + 5.18 = 9</em>
<em>9 = 9</em>
Answer:
Possible
Step-by-step explanation:
The rule for triangle side lengths is that the two shortest sides must add up to the longest side so it is possible because
3+7 = 10
Two short sides = The longest side
