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dangina [55]
3 years ago
9

The ages of some lecturers are 42 54 50 54 50 42 46 46 48 and 48find the mean age​

Mathematics
2 answers:
Virty [35]3 years ago
3 0

Answer:

48

Step-by-step explanation:

add the values of the ages of the lecturers which should give you 434 then divide by the number of lecturers in question

=480/10

=48

PIT_PIT [208]3 years ago
3 0

Answer:

48.

Step-by-step explanation:

There are a total of 10 lecturers in the list

You find the mean by dividing the sum of all the ages by 10.

The mean age = 480/10 = 48.

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Answer:

m = -9

Step-by-step explanation:

2m-10=44+8m

Subtract 2m from each side

2m-2m-10=44+8m-2m

-10 = 44+6m

Subtract 44 from each side

-10-44 = 44-44+6m

-54 = 6m

Divide by 6

-54/6 = 6m/6

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The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

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u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
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and so

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u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
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y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

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y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
What is 4(n-4)+14 equal if n=5
djyliett [7]

Answer:

18

Step-by-step explanation:

Given

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= 4(5 - 4) + 14

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Answer:

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