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frosja888 [35]
3 years ago
12

Can someone please explain?

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

This is an isosceles triangle. The angles at the base are congruent (they have the same measures).

Look at the picture.

We know: The sum of the measures of angles in a triangle is equal 180°.

Therefore we have the equation:

2x-10+2x-10+3x+25=180       <em>combine like terms</em>

(2x+2x+3x)+(-10-10+25)=180

7x+5=180           <em>subtract 5 from both sides</em>

7x=175              <em>divide both sides by 7</em>

x=25

m\angle A=2x-10\to m\angle A=2(25)-10=50-10=40\\\\m\angle C=m\angle A=40\\\\m\angle B=3x+25\to m\angle B=3(25)+25=75+25=100^o

<h3>Answer: D. m∠C = 40</h3>

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3 years ago
What are the roots of 3x2 + 10 = 4x?
sveticcg [70]

Answer:

Option C is correct.

roots of the given equation , x =\frac{2\pm i\sqrt{26}}{3}

Step-by-step explanation:

Given the equation: 3x^2+10 = 4x

We can write this equation as:

3x^2-4x + 10 =0

A quadratic equation is in the form of ax^2+bx+c =0      ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}

or

x =  \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}

or

x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}    [∴\sqrt{-1} = i

Simplify:

x =\frac{2\pm i\sqrt{26}}{3}

therefore, the roots of the given equation are; x =\frac{2\pm i\sqrt{26}}{3}

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