In the argand plane for plotting points of complex numbers we take i coefficient as x and j coefficient as y and plot as we plot regular points on the graph.

v=3i+2j

Point is (3,2) A

w =2i+3j , Point is (2,3) B

v+w = 5i +5j Point is (5,5) C

2w = 4i+6j , point is (4,6)

v-w = i-j Point (1,-1)

Please find enclosed the above points plotted on the graph.

5 0

3 years ago

Please help me immediately

marshall27 [118]

Answer:

zero of a polynomial can be defined as the points where the polynomial become 0 as a whole.

An equation formed with variables, exponents and coefficient together with operation and an equal sign is called polynomial equation.

I hope this will help you

5 0

2 years ago

For fun question

ZanzabumX [31]

Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

$f(63.97)\approxf'(64)(63.97-64)+f(64)$
$\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375$

Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...

4 0

3 years ago

Find the height of the building below by using your knowledge of trigonometry.

Lilit [14]

Answer:

50 $\sqrt{3}$

Step-by-step explanation:

The figure represents a 30-60-90 special triangle

in this special right triangle the measure of sides lengths is represented by

a, a $\sqrt{3}$ , and 2a

The side length that sees angle measure 30 is represented by a and here we see a = 50m

The height of the building, which sees angle measure 60, is equal to

50 $\sqrt{3}$

5 0

2 years ago