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Ahat [919]
2 years ago
11

Hopefully someone can help me with this question

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
4 0
This is kinda hard for me sorry, at least I get points
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Let's make the most liked question in the whole website
natali 33 [55]

Answer:

the answer is 21

7 0
3 years ago
Read 2 more answers
Your friends shuffle the cards and then deal them. Select probability of getting a red card. Select probability of getting a spa
sladkih [1.3K]

Answer:

1/2 ; 1/4

Step-by-step explanation:

Number of cards in a deck = 52

Number of red cards = 26

Number of spades = 13

Probability of event A :

P(A) = required outcome / Total possible outcomes

P( red card) = number of red cards / total cards in deck

P(red card) = 26 / 52 = 1/2

P(spade) = number of spades / total cards in deck

P(red card) = 13 / 52 = 1 / 4

7 0
3 years ago
Can I please get some help on this...I have tried to many times...
Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0
3 years ago
In the 1960s, the average price for an ear of corn was 4.17 cents. In the 1980s, the average price went up to 9.83 cents. How mu
34kurt

Answer:

the answer is 5.66 cents :)

4 0
2 years ago
Make B the subject of the relation : 1/a is equal to 1/b + c​
stealth61 [152]

Answer:

By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

1/a - 1/b = 1/c : add 1/b to both sides

1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]

1[bc/(b + c)] = a

a = bc/(b + c)

This will not work if c = -b, because then you would be dividing by zero.

Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6

a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.

Step-by-step explanation:

4 0
3 years ago
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