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mart [117]
3 years ago
11

A pizza parlor offers 5 different pizza toppings. How many different kinds of 2-topping pizzas are available?

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0
So let's pretend there is olives, pepperoni, jalapenos, sausage, and pineapple. Here is an example of an outcome chart that is useful when it comes to these type of problems.

                 sausage
                     l
pineapple-olives-pepperoni
                     l
              jalapenos
           

1. Olives and sausages
2. olives and pepperoni
3. olives and jalapenos
4. olives and pineapple
5. sausages and pepperoni
6. sausages and jalapenos
7. sausage and pineapple
8. pepperoni and jalapenos
9. pepperoni and pineapple
10. pineapple and jalapenos

There are 10 total 2 topping pizzas possible.

Now I'm hungry...

Hope this helps!

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andreev551 [17]

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Step-by-step explanation:

4 0
3 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
PLEASE HELP! The table shows the number of cans of soup shipped in different numbers of boxes.
mel-nik [20]
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.

c = 48b
96 = 48(2)
96 = 96.

Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
5 0
3 years ago
Read 2 more answers
Whats bigger 1/4 1/10
Rina8888 [55]

Answer:

1/4

Step-by-step explanation:

its bigger

5 0
3 years ago
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