Answer:
B
Explanation:
Water is essential to most bodily functions.
Answer:
Assume that
;
.
Density of the disk: approximately
.
Weight of the disk: approximately
.
Buoyant force on the disk if it is submerged under water: approximately
.
The disk will sink when placed in water.
Explanation:
Convert the dimensions of this disk to SI units:
- Diameter:
. - Thickness
.
The radius of a circle is 1/2 its diameter:
.
Volume of this disk:
.
Density of this disk:
.
indicates that the disk will sink when placed in water.
Weight of the object:
.
The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately
of water. The buoyant force on the disk will be:
.
The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.
Answer:
Time, t = 10 seconds
Explanation:
Given the following data;
Mass = 10kg
Force = 10N
Final velocity = 10m/s
Initial velocity = 0m/s
To find the time;
First of all, we would find the acceleration of the box.
Force = mass * acceleration
10 = 10 * acceleration
Acceleration = 10/10 = 1m/s²
Now, we can find the time by using the first equation of motion;
V = U + at
10 = 0 + 1t
10 = t
Time, t = 10 seconds
Therefore, it will take 10 seconds for the box to come to a complete stop.
Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding