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3 years ago

6. A 73-kg woman stands on a scale in an elevator. The

Physics

1 answer:

olga nikolaevna [1]3 years ago

3 0

Answer:

Explanation:

n = m(g +a)

n= normal force (N)

m=mass (kg)

g=acceleration of gravity

a= acceleration of elevator

rearrange:

a= n/m - g

a= (810 N/73 kg) - 9.8 m/s ^2

a= 1.3 m/s ^2 up

and the acceleration is upwards bc her weight is less than the scale reading

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Which of the following stars is likely to be the coldest? Select one: a. The white-colored star b. The orange-colored star c. Th

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P14.003A spherical gas-storage tank with an inside diameter of 8.1 m is being constructed to store gas under an internal pressur

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Answer:

The minimum wall thickness required for the spherical tank is 0.0189 m

Explanation:

Given data:

d = inside diameter = 8.1 m

P = internal pressure = 1.26 MPa

σ = 270 MPa

factor of safety = 2

Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?

The allow factor of safety:

$\sigma _{a} =\frac{\sigma }{factor-of-safety} =\frac{270}{2} =135MPa$

The minimun wall thickness:

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3 years ago

A spring stretches 0.2 cm per newton of applied force. An object is suspended from the spring and a deflection of 3 cm is observ

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Answer:

$m=1.53kg$

Explanation:

To solve this problem we use the Hooke's Law:

$F=k*\Delta x$ (1)

F is the Force needed to expand or compress the spring by a distance Δx.

The spring stretches 0.2cm per Newton, in other words:

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The force applied is due to the weight

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We replace in (1):

$mg=k*\Delta x$

We solve the equation for m:

$m=k*\Delta x/g=5*3/9.81=1.53kg$

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3 years ago

If a train travels at a speed of 40 km/h for 3 hours, how far will it travel

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3 years ago

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Answer:

Resistance will become 4 times the previous value

Explanation:

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According to ohm's law current in the circuit is given by $I=\frac{V}{R}$

So $2.4=\frac{V}{R}$ ............eqn 1

Now voltage is increased to 4 times so new voltage = 4 V

And current in the circuit is same as 2.4 A

We have to fond the resistance so that after increasing voltage current will be same

So $2.4=\frac{4V}{R_{unknown}}$ ..........eqn 2

Dividing eqn 1 and 2

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3 years ago

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