2 years ago

What is the product of the expressions? Assume y ≠0 (2y-1/y^2)(3y^2/7)

Mathematics

1 answer:

Dima020 [189]2 years ago

7 0

Answer:

(6y-3)/7

Step-by-step explanation:

(2y-1/y²)(3y²/7) first simplify 3y²/y² =3

(2y-1)(3/7) =

(6y-3)/7

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