What is the product of the expressions? Assume y ≠0 (2y-1/y^2)(3y^2/7)
1 answer:
Answer:
(6y-3)/7
Step-by-step explanation:
(2y-1/y²)(3y²/7) first simplify 3y²/y² =3
(2y-1)(3/7) =
(6y-3)/7
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