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Alexeev081 [22]
3 years ago
8

What is the product of the expressions? Assume y ≠0 (2y-1/y^2)(3y^2/7)

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0

Answer:

(6y-3)/7

Step-by-step explanation:

(2y-1/y²)(3y²/7) first simplify 3y²/y² =3

(2y-1)(3/7) =

(6y-3)/7

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