First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
I think it would just be n rad n
Answer:
-1.9393939
Step-by-step explanation:
https://www.hackmath.net/en/calculator/fraction
Answer:
Could you please put a picture of the problem?
Step-by-step explanation:
We don't know what you are trying to solve.