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vodomira [7]
3 years ago
13

On November 1, Jovel Company loaned another company $100,000 at a 6% interest rate. The note receivable plus interest will not b

e collected until March 1 of the following year. The company's annual accounting period ends on December 31, and adjustments are only made at year-end. The adjusting entry needed on December 31 is:
Mathematics
1 answer:
natita [175]3 years ago
4 0
Yes yhuuu. Hugg ut77 ftt
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Help! I need the answer and work to this :(
kompoz [17]
Since FA || BE, then angle 1 must equal angle 2 since they are corresponding angles along parallel lines where the transverse line cuts.
Thus, if angle 1 is 59, then angle 2 must also be 59 (ie D)
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Anna earns $9 an hour babysitting. She wants to buy a 16 GB iPad that is $120. Anna has saved $45 so far. How many more hours of
natta225 [31]
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8 0
3 years ago
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<img src="https://tex.z-dn.net/?f=x%20-%206%3D%20-55" id="TexFormula1" title="x - 6= -55" alt="x - 6= -55" align="absmiddle" cla
Helga [31]

Answer:

<h2>x = -49</h2>

Step-by-step explanation:

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x - 6 + 6 = -55 + 6

x = -49

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3 years ago
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A carpenter is building a rectangular shed with a fixed perimeter of 54 ft. What are the dimensions of the largest shed that can
lutik1710 [3]

Answer:

the Largest shed dimension is 13.5 ft by 13.5 ft

Largest Area is 182.25 ft²

Step-by-step explanation:

Given that;

Perimeter = 54 ft

P = 2( L + B ) = 54ft

L + B = 54/2

L + B = 27 ft

B = 27 - L ------------Let this be equation 1

Area A = L × B

from equ 1, B = 27 - L

Area A = L × ( 27 - L)

A = 27L - L²

for Maxima or Minima

dA/dL = 0

27 - 2L = 0

27 = 2L

L = 13.5 ft

Now, d²A/dL² = -2 < 0

That is, area is maximum at L = 13.5 using second derivative test

B = 27 - L

we substitute vale of L

B = 27 - 13.5 = 13.5 ft

Therefore the Largest shed dimension = 13.5 ft by 13.5 ft

Largest Area = 13.5 × 13.5 = 182.25 ft²

7 0
2 years ago
Solve 2a−5≤13.<br><br> help please
rosijanka [135]

Answer:

a≤9

Step-by-step explanation:

3 0
3 years ago
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