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Ksivusya [100]
3 years ago
8

To change knots per hour, use the expression 1.15k, where k is the speed in in knots per hour. A plane is flying at 300 knots pe

r hour. How fast is that plane flying in miles per hour. Explain step by step.
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0
1.15(300).
Substitute k for 300, since the plane is flying 300 knots per hour, and k=knots per hour.

1.15(300)=345 miles per hour
After multiplying, 300 by 1.15, you get 345 miles per hour. This is the speed of the plane from Knots to MPH (Miles Per Hour).
8090 [49]3 years ago
4 0
Since the plane is flying 300 knots per hour.
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Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s
garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

X= Customers that arrive within the hour

and since X follows a Poisson distribution with mean \alpha = 7

Therefore,

E(X)= 7

& V(X)=7

Let Y = the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

Y=10X

For a random variable X and a constant c,

E(cX)=cE(X)\\V(cX)=c^2V(X)

Thus,

E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution Y is,

p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7}  .\frac{1}{10}  \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002

0.002 is small enough, and the function \frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}  gets even smaller when k increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0
3 years ago
Please answer if known - thnx so much
zheka24 [161]
The answer is 36. You can multiply top and bottom by 3, or cross multiply and divide.

3 0
4 years ago
Read 2 more answers
Find the solution set for the following equation. <img src="https://tex.z-dn.net/?f=-%5Csqrt%28x%29%3D5" id="TexFormula1" title=
andrey2020 [161]

Answer:

Solution set = {25}

Step-by-step explanation:

=> -\sqrt{x} =5

Dividing both sides by -1

=> \sqrt{x} = -5

Taking square on both sides

=> x = 25

<em><u>Solution set = {25}</u></em>

3 0
3 years ago
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