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dlinn [17]
3 years ago
11

Plants and animals are both _____.

Biology
2 answers:
Iteru [2.4K]3 years ago
5 0
Plants and animals are both, made of cells
kolezko [41]3 years ago
4 0
Plants and animals are both "organisms" or "living organisms" if you prefer.

An organism is basically a group of different organs functioning together (hope this was the easiest way to explain it).

Hope it helped,

Happy study/ homework/ exam!
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Reverse transcriptase is an enzyme utilized by many retroviruses. This enzyme most likely demonstrates which type of activity
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Answer:

The activity of speed up the process.

Explanation:

Reverse transcriptase is an enzyme encoded from the genetic material of retroviruses that accelerate or speed up the process of  transcription of retrovirus ribonucleic acid into deoxyribonucleic acid. Reverse transcriptase enzyme is also called RNA-directed DNA polymerase. Some retroviruses such as human immunodeficiency virus (HIV) and avian myeloblastosis virus used this Reverse transcriptase enzyme.

7 0
3 years ago
Random thought, should fingers have FINGERS?
Bad White [126]
B). Brainly said I’m wrong when I tried submitting it
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2 years ago
Which statement correctly summarizes Wegener’s theory of continental drift?
GuDViN [60]

The correct answer would be D), over millions of years, Pangaea broke apart and drifted to form the seven continents.

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3 years ago
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In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

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3 years ago
Variety in genotypes across a population describes
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Genetic diversity.....
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