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Bas_tet [7]
3 years ago
12

What is the slope of the line passing through the points (–1, 3) and (4, –7)?

Mathematics
2 answers:
Firdavs [7]3 years ago
6 0
slope=\frac{y_2-y_1}{x_2-x_1}\\\\ 
(x_1,y_1)=(-1,3)\\ 
(x_2,y_2)=(4,-7)\\\\
 slope=\frac{-7-3}{4+1}=\frac{-10}{5}=-2\\\\
Slope\ is\ equal\ to\ -2.\\Answer\ is\ D.

WINSTONCH [101]3 years ago
4 0
The answer is a.2 because this coordinate is the only one along the slope
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Notice that the 2 graphs intersect when x = 12 minutes.  That's your answer.
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What is the length of AB?
Rus_ich [418]

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What is an equation of the line that is perpendicular to y+1=-3(x-5) and passes through the point 4,-6
Oliga [24]

Answer:

y=\frac{1}{3}x-\frac{16}{3}

Step-by-step explanation:

Arranging the given equation in slope-intercept form ( y = mx + b ):

y+1=-3(x-5)\\y+1=-3x+15\\y=-3x+15-1\\y=-3x+14

<em>We know that the perpendicular line would have a slope (m) that is </em><em>negative reciprocal </em><em>of this (\frac{1}{3}). Thus we can write the perpendicular line's equation as  y=\frac{1}{3}x+b. </em>

<em />

<em>Now putting x = 4 and y = -6 into the equation, we can solve for b:</em>

<em>y=\frac{1}{3}x+b\\-6=\frac{1}{3}(4)+b\\-6=\frac{4}{3}+b\\b=-6-\frac{4}{3}\\b=-\frac{16}{3}</em>

<em />

Thus, the equation of the perpendicular line is  y=\frac{1}{3}x-\frac{16}{3}

6 0
3 years ago
Read 2 more answers
Need help fast!!!
Arturiano [62]

x = -2

so 0.5 x (2-(-2)) = 0.5 x 4 = 2

7 0
4 years ago
Part of a school’s stage is shaped like a sector of a circle, as shown below. The students do not yet know the exact dimensions
Natasha2012 [34]

Answer:

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Step-by-step explanation:

<u>Use the formula:</u>

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<u>As per given:</u>

l = 12 feet, r = 10 feet

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  • radians = π rad *12/(2π*10) = 0.6 rad
8 0
3 years ago
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