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3 years ago

What is the slope of the line passing through the points (–1, 3) and (4, –7)?

2 answers:

6 0

$slope=\frac{y_2-y_1}{x_2-x_1}\\\\ 
(x_1,y_1)=(-1,3)\\ 
(x_2,y_2)=(4,-7)\\\\
 slope=\frac{-7-3}{4+1}=\frac{-10}{5}=-2\\\\
Slope\ is\ equal\ to\ -2.\\Answer\ is\ D.
$

WINSTONCH [101]3 years ago

4 0

The answer is a.2 because this coordinate is the only one along the slope
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6, 3, 4, 7, 3, 7, 8, 5, 7 i. Find the median ii. Find the mean iii. Find the modal mark

4vir4ik [10]

Answer:

i. 6

ii. $5\frac{5}{9}$

iii. 7

Step-by-step explanation:

First organize the data from least to greatest. 3,3,4,5,6,7,7,7,8

To find the median, remove the extremes from the data over and over.

3,4,5,6,7,7,7

4,5,6,7,7

5,6,7

To find the mean, add all of the numbers and divide by 9

3+3+4+5+6+7+7+7+8=50

50/9= $5\frac{5}{9}$

To find the modal mark, simply find the number present most in the data set: 7(occurs 3 times)

Hope it helps <3

3 0

3 years ago

Upon completion of an experiment a student realizes that the technique used for measuring the length and width of a rectangle ha

eduard

Answer:

809.4cm²

Step-by-step explanation:

Given the following :

Systematic error = 3.8cm (The measured length is always more than the actual length.)

Most probable dimension :

Width = 85.7 cm

Length = 123.5 cm

Hence most probable area of Rectangle :

Area = Length × Width

Area = 85.7cm × 123.5cm = 10583.95 cm²

Dimension due to Systematic error :

Length = (85.7cm + 3.8cm) = 89.5cm

Width = (123.5cm + 3.8cm) = 127.3cm

Area = Length × width

Area = ( 89.5cm × 127.3) = 11393.35cm²

Systematic error of the area :

value of area with Systematic error - Probable value of area :

11393.35cm² - 10583.95 cm² = 809.4cm²

6 0

3 years ago

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.