I’m so confused help Distribute: 7(t+4)

Mathematics

2 answers:

IceJOKER [234]2 years ago

8 0

Answer:

7t+28

Step-by-step explanation:

multiply each term in the parentheses by 7

7t+7×4

multiply the numbers

7t+28

ZanzabumX [31]2 years ago

4 0

<h3>Answer: 7t + 28</h3>

Explanation:

Multiply the outer term 7 by each term inside the parenthesis.

7 times t = 7*t = 7t
7 times 4 = 7*4 = 28

We then add up those results, combining like terms if possible.

That's how we get to 7t + 28

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Find the equation of the line that passes through the points (-4, 2) and (1, -8). Use the form y=Mx+b

GuDViN [60]

ANSWER: Y=-2x-6

EXPLANATION:
(2- -8)/(-4-1)= 10/-5= -2

2=-2(-4) +b
2= 8 + b
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5 0

3 years ago

Help me please thanks before

sdas [7]

-17 + 28 = 11

hope this helps, give brainliest

8 0

3 years ago

Read 2 more answers

Determine the arithmetic sequence if the fourth term is negative six and the eleventh term is negative thirty four

ICE Princess25 [194]

An arithmetic sequence takes the form

$a_n=a_{n-1}+d$

where $d$ is the common difference between terms. You can solve for $a_n$ in terms of any of the previous terms of the sequence:

$a_n=a_{n-1}+d\implies~a_n=a_{n-2}+2d\implies~a_n=a_{n-3}+3d\implies\cdots\implies~a_n=a_{n-k}+kd$

for some integer $1\le k\le n-1$

Continuing in this way, you know that the sequence can be defined explicitly in terms of the first term $a_1$

$a_n=a_1+(n-1)d$

Given that the 4th term is $a_4=-6$ and the 11th term is $a_{11}=-34$ , you have the following system of equations.

$\begin{cases}-6=a_1+(4-1)d\\-34=a_1+(11-1)d\end{cases}$

Solving this system for the two unknowns yields $a_1=6$ and $d=-4$ .

So, the sequence is given explicitly by

$a_n=6+(n-1)(-4)=-4n+5$