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seropon [69]
3 years ago
15

((7,-1) and (21,-5) what is the equation in slope intercept form?

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

y=-2/7x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-5-(-1))/(21-7)

m=(-5+1)/14

m=-4/14

simplify

m=-2/7

y-y1=m(x-x1)

y-(-1)=-2/7(x-7)

y+1=-2/7(x-7)

y=-2/7x+2-1

y=-2/7x+1

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If each interior angle of the regular polygon measures 168º, how many sides does the polygon have?
iogann1982 [59]

Answer: Hello, there! Sorry Im late But your answer is Below

30 sides Would be the correct answer

Step-by-step explanation:

t has 30 sides. The formula (n-2)×180 can be used to find the sum of the interior angles of ANY polygon where n is the number of sides in the polygon.

Hope this Helps!!

Have a great day!!!

5 0
3 years ago
Simplify this expression.
amm1812

Answer: 0.88

Step-by-step explanation:

Okay -5.37 + 8.14 = 2.77 ( you can simply plug this into the calculator or you could switch the problem around so it’s 8.14 - 5.37, either way you’ll get 2.77)

And then you take 2.77 -1.89 = 0.88

So 0.88 is your answer

7 0
2 years ago
Please tell me what to multiply by like the equations (finding the surface area)
cupoosta [38]
Length time weith time highth
3 0
3 years ago
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5 0
3 years ago
A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

Step-by-step explanation:

Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

Hence, The required fraction = \dfrac18

5 0
2 years ago
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