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3 years ago

Someone help please!!

Mathematics

1 answer:

mash [69]3 years ago

8 0

Answer:

y = 6 - 2x

6 - 2 X 0 = 6

6 - 2 X 1 = 4

6 - 2 X 2 = 2

6 - 2 X 3 = 0

6 - 2 X 4 = -2

6 - 2 X 5 = -4

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All possible solutions for 6sin^2(3x)=-3

vova2212 [387]

Answer:

Please check the step-by-step explanation for the answer.

Step-by-step explanation:

Considering the trigonometric expression

$6sin^2\left(3x\right)=-3$

Steps

$\mathrm{Let:\:}\sin \left(3x\right)=u$

$6u^2=-3$

$\mathrm{Divide\:both\:sides\:by\:}6$

$\frac{6u^2}{6}=\frac{-3}{6}$

$u^2=-\frac{1}{2}$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$u=\sqrt{-\frac{1}{2}},\:u=-\sqrt{-\frac{1}{2}}$

$\mathrm{Simplify}\:\sqrt{-\frac{1}{2}}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt{-a}=\sqrt{-1}\sqrt{a}$

$=\sqrt{-1}\sqrt{\frac{1}{2}}$

$\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i$

$=i\sqrt{\frac{1}{2}}$

Similarly,

$-\sqrt{-\frac{1}{2}}=\quad -i\sqrt{\frac{1}{2}}$

So,

$u=i\sqrt{\frac{1}{2}},\:u=-i\sqrt{\frac{1}{2}}$

$\mathrm{Substitute\:back}\:u=\sin \left(3x\right)$

$\sin \left(3x\right)=i\sqrt{\frac{1}{2}},\:\sin \left(3x\right)=-i\sqrt{\frac{1}{2}}$

So,

$\sin \left(3x\right)=i\sqrt{\frac{1}{2}}\quad :\quad \mathrm{No\:Solutions}$

and

$\sin \left(3x\right)=-i\sqrt{\frac{1}{2}}\quad :\quad \mathrm{No\:Solutions}$

$\mathrm{Combine\:all\:the\:solutions}$

$\mathrm{No\:Solution\:for}\:x\in \mathbb{R}$

Keywords: trigonometric equation, solution

Learn more about trigonometric equation solution from brainly.com/question/1687218

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5 0

4 years ago

Can anyone help me with this

ruslelena [56]

(1/2)/(19/6)
1/2 * 6/19
3/19

7 0

3 years ago

Many fast-food restaurants have soft drink dispensers with preset amounts, so that when the operator merely pushes a button for

antiseptic1488 [7]

Answer:

Alternative hypothesis is that Worker productivity is higher with automatic dispensers.

The Rank for Group1 is 115.5 and Group 2 is 55.5.

Conclusion is that Worker productivity is higher with automatic dispensers.

Step-by-step explanation:

The null and alternative hypotheses are

H0: Group1 ≤ Group2 against the claim

Ha: Group1 > Group2

Alternative hypothesis is that Worker productivity is higher with automatic dispensers.

Calculations:

Group1 Group2

Sample Mean x ` 139.22 114.67

Sample size n 9 9

Sample SD 18.21 11.937

Rank 115.5 55.5

U 10.5 70.5

The Rank for Group1 is 115.5 and Group 2 is 55.5.

1. H0 hypothesis

As p-value < alpha and Z lies in the critical region, H0 is rejected.

The randomly selected value of Group1's population is considered have greater productivity than the randomly selected value of Group2's population.

2. P-value

The p-value equals 0.0046.

3. Test statistics

Z= u-μ+c/σ

The critical region for one tailed test for z at 0.01 significance level is

z > 2.33.

The test statistic Z equals 2.6063, which lies in the critical region of acceptance z> 2.326

4. Conclusion

As the calculated test statistic lies in the critical region H0 is rejected and it is concluded that

Worker productivity is higher with automatic dispensers. 

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3 years ago

How does: 12 + pi - 9pi/8 Become 12 - pi/8 Thanks for your help.

bixtya [17]

9pi/8 = 8pi/8 + pi/8 = pi + pi/8

12 + pi - 9pi/8 = 12 + pi - pi - pi/8

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3 years ago

angle a and b are supplementary angles. angle where a = 30+2x and b =x what is the measure of b degress

bekas [8.4K]

Answer:32 times 4 - 8 in degrees

Step-by-step explanation:

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3 years ago