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anyanavicka [17]
3 years ago
13

The sun shines at a 30° angle to the ground. To the nearest inch, how long is the shadow cast by a 72-inch tall fence post?

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

the shadow cast by a 72-inch tall fence post is of 125 inch!

<u>Step-by-step explanation:</u>

Here we have , The sun shines at a 30° angle to the ground. To the nearest inch, We need to find how long is the shadow cast by a 72-inch tall fence post. Let's find out:

According to question we have a right angle triangle with following parameters :

Perpendicular = 72 inch\\Base = ?\\x =30

We know that

⇒ Tanx = \frac{Perpendicular}{Base }

⇒ Tan30 = \frac{72}{Base }

⇒ \frac{1}{\sqrt{3} } = \frac{72}{Base }

⇒ Base = 72\sqrt{3} inch

⇒ Base = 124.7 inch

Rounding off we get :

⇒ Base = 125 inch

Therefore , the shadow cast by a 72-inch tall fence post is of 125 inch!

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The function y = x2 is transformed to y = (x + 4)2. Which statement is true about the transformed function? It is an even functi
xxMikexx [17]
Even function: f(-x) = f(x). If you replace x by -x you should find the same function.
Odd function: f(-x) = -f(x). If you replace x by -x you  find the same function with opposite sign;
Is f(-x) = f(x)?
f(x) = (x+4)² =  x² + 8x +16
f(-x) = (-x+4)² = x² - 8x + 16, then it's not an even function

Is f(-x) = -f(x)?
f(-x) = (-x+4)² = x² + 8x + 16 , then it's not an odd function
It is neither an even nor an odd function
7 0
4 years ago
Help please word problem...show work please
Alona [7]
A) you must plug in 50 for variable F and solve for C

C=\frac{5}{9}(50-32)
C=\frac{5}{9}(18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius 

B) you must solve the equation for F

C= \frac{5}{9}(F-32)
C/\frac{5}{9}=F-32
C/\frac{5}{9}+32=F
F= C/\frac{5}{9}+32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F=\frac{9}{5}C +32

now you just plug in 50 for the variable C in the new equation

F= \frac{9}{5}(50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

6 0
4 years ago
Rectangle ABCD is similar to rectangle RSTU .
Alenkasestr [34]

Answer:

The scale factor of a dilation from ABCD to RSTU is \frac{1}{2}

Step-by-step explanation:

We know that the rectangle ABCD is similar to rectangle RSTU.

Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS

Working with the lengths of the sides :

DC.(Scale factor) = UT

AB.(Scale factor) = RS

Replacing with the values of the lengths (Scale factor : SF) :

DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

Notice that the scale factor is dimensionless.

We can verify this result with the sides AD and BC :

AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

The scale factor (SF) is \frac{1}{2}

7 0
3 years ago
Read 2 more answers
What's the comparison to 5 + 4
amm1812
6 + 3 or you could do 4.5 + 4.5. but the first one is probably what they're looking for.
8 0
4 years ago
Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice
Romashka [77]

Answer:

a)   S=50

    P(X)=0.02

b)  P(W,M,C)=8*10^-^6

c)  P(W_2_3)=1.18*10^-^3

Step-by-step explanation:

From the question we are told that

Sample space S=50

Sample size n=30

a)Generally the sample space S is

S=50

The probability measure is given as

P(X)=\frac{1}{50}

P(X)=0.02

b)

Generally the probability that  the class hangs Wisconsin’s flag on Monday, Michigan’s flag on Tuesday, and California’s flag on Wednesday is mathematically given as

Probability of each one being hanged is

P(X)=\frac{1}{50}

Therefore

P(W,M,C)=\frac{1}{50} *\frac{1}{50}* \frac{1}{50}

P(W,M,C)=\frac{1}{125000}

P(W,M,C)=8*10^-^6

c)Generally the probability that Wisconsin’s flag will be hung at least two of the three days is mathematically given as

Probability of two days hung +Probability of three days hung

Therefore

P(W_2_3)=^3C_2 (1/50) * (1/50) * (49/50) +^3C_3 (1/50) * (1/50) *(1/50)

P(W_2_3)=148 / 125000

P(W_2_3)=1.18*10^-^3

3 0
3 years ago
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