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QveST [7]
3 years ago
7

The function y = x2 is transformed to y = (x + 4)2. Which statement is true about the transformed function? It is an even functi

on. It is an odd function. It is neither an even nor an odd function. It is both an even and an odd function.
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
Even function: f(-x) = f(x). If you replace x by -x you should find the same function.
Odd function: f(-x) = -f(x). If you replace x by -x you  find the same function with opposite sign;
Is f(-x) = f(x)?
f(x) = (x+4)² =  x² + 8x +16
f(-x) = (-x+4)² = x² - 8x + 16, then it's not an even function

Is f(-x) = -f(x)?
f(-x) = (-x+4)² = x² + 8x + 16 , then it's not an odd function
It is neither an even nor an odd function
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Notice how on both sides of the equation there is one coefficient (number being multiplied by x) and a constant (just a plain number). You want all constants to be on one side and all coefficients on the other. He’s how do to that:
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I am choosing that all constants will be on the right side, so I will do the inverse operation of any constant on the left side to remove it. Here, a constant on the left side is 14. I will subtract 14 from both sides of the equation. Positive 14 minus 14 is zero, so it cancels out and removes it.
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