Help please word problem...show work please
1 answer:
A) you must plug in 50 for variable F and solve for C
C=
(50-32)
C=
(18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius
B) you must solve the equation for F
C=(F-32)
C/=F-32
C/+32=F
F= C/+32
dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as
F=
C +32
now you just plug in 50 for the variable C in the new equation
F=(50) +32
F= 90 + 32
F= 122
50 degrees celsius is equal to 122 degrees fahrenheit
hope this helped!
C=
C=
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius
B) you must solve the equation for F
C=
C/
C/
F= C/
dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as
F=
now you just plug in 50 for the variable C in the new equation
F=
F= 90 + 32
F= 122
50 degrees celsius is equal to 122 degrees fahrenheit
hope this helped!
You might be interested in
Answer:
20 minutes should spend on walking and 30 minutes on running.
Step-by-step explanation:
Let x represents the minutes spent on walking and y represents the minutes spent on running,
∵ He burns 4 cal/min walking and 10 cal/min running,
So, the total calories burnt,
Z = 4x + 10y
Which has to be maximised.
Now, he walks between 10 and 20 min each day,
i.e. 10 < x < 20,
Also, he runs between 30 and 45 min each day,
i.e. 30 < y < 45,
By graphing 10 < x < 20 and 30 < y < 45,
We obtained the vertices of feasible region,
(10, 45), (20, 45), (10, 30) and (20, 30)
At (10, 45),
Z = 4(10) + 10(45) = 40 + 450 = 490,
At (20, 45),
Z = 4(20) + 10(45) = 80 + 450 = 530,
At (10, 30),
Z = 4(10) + 10(30) = 40 + 300 = 340,
At (20, 30)
Z = 4(20) + 10(30) = 80 + 300 = 380
Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.
