<h3>The time in fourth race is 43.04 seconds</h3>
<em><u>Solution:</u></em>
Given that,
Shelly is trying to improve her running time for a track race
She ran the first race in 43.13 seconds
Her time was 43.1 seconds in the second race and 43.07 seconds in the third race
<em><u>Therefore, pattern is:</u></em>
43.13, 43.1, 43.07 , ..
<em><u>Find the difference between each terms</u></em>
d = 43.13 - 43.1 = 0.03
d = 43.1 - 43.07 = 0.03
Thus the difference is same
<em><u>If this pattern continues what will shellys time be in the fourth race?</u></em>
Fourth race = third race - 0.03
Fourth race = 43.07 - 0.03 = 43.04
Thus the time in fourth race is 43.04 seconds
2. -28
5. -60
8. -135
The answers are above. :)
Log N^3 = 3 log N
using the theorem log a^2 = 2 log a
