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liubo4ka [24]
3 years ago
6

Lamar lives Three-fourths of a mile from school. His best friend, Kendrick, lives Seven-eighths of a mile away from the school.

Use this information to answer the questions below. Who lives farther from the school? How much farther does he live?
free points btw not a lot but yea (dont answer saying thanks for the points or i will report you ) :)
Mathematics
2 answers:
Alex_Xolod [135]3 years ago
8 0
Kendrick lives farther from the school. He lives 1/8 mile farther from school than Lamar.
Bezzdna [24]3 years ago
6 0

Answer:

1.) who lives further... definitely Kendrick

2.)4- fourths further    

Step-by-step explanation:

well the numbers are bigger which means futher and

all i really did was add to three till i got to 7 and

add to 4 till i got to 8 which was 4

hope this helps

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Which of the following are ordered pairs for the equation y = 1/3x - 1?
stellarik [79]

Answer:

answer is the 2nd one

Step-by-step explanation:

y = 1/3(3) - 1 = 1 - 1 = 0   (3,0)

y = 1/3(0) - 1 = 0 - 1 = -1   (0, -1)

y= 1/3(6) - 1 = 2 - 1 = 1     (6, 1)

8 0
3 years ago
In my closet I have 12 pair of pants, 9 skirts, and 15 shirts. What is the ratio of 'shirts' to 'skirts and pants'?
vekshin1

Answer:

15:9

Step-by-step explanation:

Because you have a total of 15 shirts and a total of 9 skirts.

7 0
3 years ago
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Find the mean of each data set. 11,16,17,20,26
Pavel [41]

Answer:

The mean is 18

Step-by-step explanation:

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8.v = r 2 πh 3

Step-by-step explanation:

7 0
3 years ago
Which ordered pair is a solution of linear equations?
Bingel [31]

Answer:

\{\frac{2}{3}, \frac{1}{5}\}

ordered pair is the Solution to the given System.

Step-by-step explanation:

Given:

\frac{1}{2}x- \frac{3}{4}y= \frac{11}{60} ...........Equation( 1 )\\ \\\frac{2}{5}x+ \frac{1}{6}y= \frac{3}{10} ...........Equation( 2 )\\

To Check:

Which ordered pair is the Solution to the given System. ?

Solution:

If  \{\frac{2}{3}, \frac{1}{5}\}

is the Solution then it must satisfy the given equation. i.e .Left Hand Side (L.H.S) must be Equal to Right Hand Side (R.H.S) of both the given equation for

\{x=\frac{2}{3}, y=\frac{1}{5}\}

∴ For Equation ( 1 )

L.H.S=\frac{1}{2}\times \frac{2}{3}- \frac{3}{4}\times \frac{1}{5}\\\\\\=\frac{1}{3} -\frac{3}{20} \\\\=\frac{20-9}{20\times 3}\\\\ =\frac{11}{60} \\= R.H.S

∴ Left Hand Side = Right Hand Side

Hence,

\{x=\frac{2}{3}, y=\frac{1}{5}\}

The solution.

∴ For Equation ( 2 )

L.H.S=\frac{2}{5}\times \frac{2}{3}+ \frac{1}{6}\times \frac{1}{5}\\\\\\=\frac{4}{15} -\frac{1}{30} \\\\=\frac{120+15}{15\times 30}\\\\= \frac{135}{450}\\ \\\\=\frac{3}{30}\\ \\= R.H.S

∴ Left Hand Side = Right Hand Side

Hence ,

\{x=\frac{2}{3}, y=\frac{1}{5}\}

The solution.

For other Solutions  we do not have Left Hand Side equal to Right Hand Side.  

i.e  Left Hand Side ≠ Right Hand Side

Hence Not a Solution.

5 0
3 years ago
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