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PilotLPTM [1.2K]
4 years ago
13

Question 3 A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: →+2VO+2aq+4H+aqFes+2VO+2aq+2H2

OlFe+2aq Suppose the cell is prepared with 2.22 M VO+2 and 3.55 M H+ in one half-cell and 5.56 M VO+2 and 6.55 M Fe+2 in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
Chemistry
1 answer:
svp [43]4 years ago
4 0

Answer:

E = +1.430  V

Explanation:

The given cell reaction is written as:

2VO²⁺(aq) + 4H⁺(aq) + Fe(s)---> 2VO₂⁺(aq) + 2H₂O(l) + Fe²⁺(aq)

E⁰cell = E⁰_{VO₂/Vo₂⁺}  - E⁰_{Fe²⁺/Fe}

= + 1.00 - ( - 0.447) = + 1.45 V

From Nernst equation...

E = E⁰cell - (RT/nF) lnQ

where, Q = [products]/[reactants]

= [Fe²⁺][VO₂⁺]²/[VO²⁺]²[H⁺]⁴

Q= (6.55*5.56)/(2.22*3.55)

 = 36.418/7.881

 = 4.621

T = 25 + 273 = 298K

at 298K the above equation could also be written as...

E = E⁰cell - (0.0592/n) log Q

n is number of electrons transferred and it is 2. Let's plug in the values...

E = 1.45 - (0.0592/2) log 4.621

E = 1.45 – (-0.01968)

E = +1.430  V

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2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃)

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4 years ago
For the reaction ag2s(s) ⇌ 2 ag+ (aq) + s2- (aq), keq = 2.4 × 10-4 and the equilibrium concentration of silver ion is [ag+] = 2.
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Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

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The expression of K will be,

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[S^{2-}]=3.8\times 10^{-3}M

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4 0
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Answer:

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1 mol of N₂ produced 2 moles of ammonia

So, If I have 1 mol, I'll produce the same amount

2 moles of NH₃ = Mol . Molar mass

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