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Natalka [10]
3 years ago
15

Divide. express your answer in simplest form.3 5/6 ÷ 3 3/4​

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

\frac{46}{45}

Step-by-step explanation:

3 5/6 ÷ 3 3/4​ = 46/45

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Solve for w in the proportion.<br> W/14 = 21/42 W = ?
Nataly [62]

Answer:

W = 7

Step-by-step explanation:

1) Simplify 21/42 into 1/2

w/ 14 = 1/2

2) Multiply both sides by 14.

W = 1/2 · 14

3) Simplify

W = 14/29

4) Simplify (again)

W = 7

8 0
3 years ago
Simplify 5(cis7pi/4)^4
solniwko [45]

Answer:

  -625

Step-by-step explanation:

The magnitude gets raised to the power, and the angle gets multiplied by the power:

  5(cis7pi/4)^4 = (5^4)cis(4·7π/4) = 625cis(7π) = 625cis(π) = -625

5 0
3 years ago
Mary had a birthday party, after the party she had 1/5 of the cake left over. Her 3 uncles shared the leftover cake equllay. Whi
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Answer:

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Step-by-step explanation:

3 0
3 years ago
What is a way that you use synthesis in your everyday life?
Korolek [52]

Answer:

shopping for a car

Step-by-step explanation:

lets say you want to buy a new car, you ask yourself, hmm, which one is the best for me. or which car has the best milage. those type of things

4 0
3 years ago
WILL MARK BRAINIEST!!1 PLZ HELP!25 points!!! The coordinate grid shows points A through K. What point is a solution to the syste
marishachu [46]

Answer:

A, C, D and K

Step-by-step explanation:

Inequalities:

y ≤ −2x + 10  and  y >1/2x-2

<u>Finding zeros for the first inequality:</u>

  • x=0 ⇒ y= 10, point (0, 10)
  • y=0 ⇒ x= 5, point (5, 0)
  • Locating these 2 points and connecting to get the first line.

Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.

<u>Finding zeros for the second inequality:</u>

  • x=0 ⇒ y= -2, point (0, -2)
  • y= 0 ⇒ x= 4, point (4, 0)
  • Locating these points and connecting to get the second line.

Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.

Now we have the space of intersection of the above inequalities.

So the points in same section are the solution.

They are:

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See attached for explanation

7 0
4 years ago
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