30=1/2 inch
60=1/2x2=1 inch
90=1/2x3=1 1/2
shortest side is 1/2 inch, medium side is 1 inch, longest is 1 1/2
2x^4
13b-10
5y+10
5a^3
2b^2+8a
can you please add the answers to choose from? I'd like to help
Answer:
The surface area is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces.
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have


substitute the values
![SA=0.4^{2}+4[\frac{1}{2}(0.4)(0.6)]=0.64\ m^{2}](https://tex.z-dn.net/?f=SA%3D0.4%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%280.4%29%280.6%29%5D%3D0.64%5C%20m%5E%7B2%7D)
Answer:
- ABCD is a rhombus, and a parallelogram
==================================
<h3>Given </h3>
- Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)
First, plot the points (see attached picture).
Then, connect all the points.
<h3>We see that:</h3>
- Opposite sides are parallel,
- Diagonals are perpendicular.
From our observation the figure is rhombus.
Let's confirm it with the following.
1) Find midpoints of diagonals and compare.
- AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
- BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2
The midpoint of both diagonals is same (- 2, 2).
2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.
- m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
- m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3
- m(AC) × m(BD) = 3/4 * (- 4/3) = - 1
<u>Confirmed.</u>
So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.