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densk [106]
4 years ago
14

Find dy/dx by implicit differentiation for x + 2y = xy.

Mathematics
1 answer:
Stella [2.4K]4 years ago
4 0
Ok to find dy/dx of x+2y=xy we take derivative of both sides with respect to x

1+2dy/dx = x*dy/dx +y*dx/dx
1+ 2dy/dx = x*dy/dx + y* 1
2dy/dx +1 = x*dy/dx + y

2y’ + 1 = xy’ + y

2y’ + 1 - xy’ = y

2y’ -xy’ = y - 1

y’(2-x) = y - 1

so we get finally

y’= (y-1)/(2-x)

Hope this helps you understand the concept! Any questions please ask! Thank you so much!!
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What is the answer for 3\5=a+5\25
IceJOKER [234]

Answer:

a = 2/5 = 0.400

Step-by-step explanation:

Step  1  :

           1

Simplify   —

           5

Equation at the end of step  1  :

 3          1

 — -  (a +  —)  = 0

 5          5

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  5  as the denominator :

         a     a • 5

    a =  —  =  —————

         1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

a • 5 + 1     5a + 1

—————————  =  ——————

    5           5  

Equation at the end of step  2  :

 3    (5a + 1)

 — -  ————————  = 0

 5       5    

Step  3  :

           3

Simplify   —

           5

Equation at the end of step  3  :

 3    (5a + 1)

 — -  ————————  = 0

 5       5    

Step  4  :

Adding fractions which have a common denominator :

4.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 - ((5a+1))     2 - 5a

————————————  =  ——————

     5             5  

Equation at the end of step  4  :

 2 - 5a

 ——————  = 0

   5  

Step  5  :

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2-5a

 ———— • 5 = 0 • 5

  5  

Now, on the left hand side, the  5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2-5a  = 0

Solving a Single Variable Equation :

5.2      Solve  :    -5a+2 = 0

Subtract  2  from both sides of the equation :

                     -5a = -2

Multiply both sides of the equation by (-1) :  5a = 2

Divide both sides of the equation by 5:

                    a = 2/5 = 0.400

One solution was found :

                  a = 2/5 = 0.400

Processing ends successfully

plz mark me as brailiest :)

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